UAF WRE One Liner Questions. UAF WRE One Liner Questions for Postgraduate Entry Test Preparation. UAF WRE One Liner Questions for GAT Test. UAF WRE One Liner Questions for GRE Test. UAF WRE One Liner Questions for M.sc Students.
Statement | Answer |
---|---|
In order to draw the perpendicular from the chain line following method is used———————- | 3, 4, 5 method |
In order to draw the perpendicular from the point on the chain line following method is the used—————— | Tape swing method |
When chain age is obstructed but the vision is free between the two points on the chain line then the length of the line between such points can be found by the———————- | By drawing a large right angle triangle |
Which tool is the best to measure the distance in the windy zone————-? | Engineer’s chain |
The number of the links in the Engineer’s and the Gunter’s Chain————– | Are the same |
The ratio of the Hoop stress and axial stress varies for the thin walled pressure vessel—————— | 2 to 1 |
Difference between the thin walled and hick walled pressure vessel is the————— | Vessels having thickness to the diameter ratio greater than 0.1 are thick walled pressure vessel |
The using the concept of the thin shell of revolution, which statement is the true for the radius used—————– | Both the radius has variable values |
For the calculation of the stress in the thin walled pressure vessel————- | Only internal pressure is the important |
The keeping in view the torsional loading, tick the false statement—————– | The plane segment remain plane after application of load on square rods |
The keeping in view the torsional loading, the polar moment of the inertia depends upon the————— | The shape of shaft |
Diameter of the shaft is selected on the basis of the————— | On the basis of the shear stress or angle of twist which returns the higher value of the diameter |
Shear stress developed in the shafts are based on the———– | None of these are correct |
The hollow shaft will transfer more torque if it——————– is the same as the solid shaft | None of these are correct |
The simply supported beam is the————– | Both the end roller supported |
The point Load is the one——————- | Which act on the area negligible as compare to the total area of the object? |
The bending moment is produced the———– | Due to the external forces and moments |
The shear force is the——— | Working perpendicular to beam axis |
The beam is of 10 meters length out of the distributed load of 100 N was spread over 8 meters. The equivalent point load is the————— | 100 N |
Which statement for the Neutral Axis is not the true————? | An axis passes through the max stress region |
The maximum bending moment is the————– | Depends upon the loading |
In case of the T beam, the stress distribution is based on the————– | The distance from the geometrical center of the beam |
The maximum bending moment is the———————- | At the point where shear force is the zero |
For the distributed load————– | The bending moment diagram is drawn with curve lines |
If there is the point and distributed load acting together on the beam, then the—————– | The bending moment diagram is drawn with curve lines |
If there is the point and distributed load acting together on the beam, then the————— | Shear force diagram will have inclined lines with the sudden decline as vertical line at the point where the point load is acting |
The bending moment and the shear force diagram depends upon the————- | Acting forces and the end supports types |
Which factor depends upon the depressions of terrain and the causes water logging? | Irregular Topography |
The spring torsion testing machine is used to the———- | Measure the torque produced in the spring at the different angles |
In the torsional testing machine of the shafts——– | Angle of the twist can be changed |
Which thing decided the category of the column as short, intermediate & long————? | Slenderness ratio |
Relationship between the equivalent length and actual length of the column is the——————– | The depends upon the end connections |
Relationship between the maximum allowable load and Euler buckling load for the column is the———– | Euler Buckling load is greater than the maximum allowable load |
Machine used to draw the stress strain relationship is known as the———– | Universal Testing Machine |
The cement briquette testing machine apply the——— | The compressional load |
While calculating the deformation under the axial loading; which parameter will be the changed if the shape of the object (machine element) under the axial loading changed———– | Cross sectional area |
While calculating the deformation under axial loading, which parameter will be the changed if the material of the object (machine element) under the axial loading changed————– | Modulus of elasticity |
What would be factor of the safety if stress developed in the machine element under the axial loading is 80 MPa if the element is made of the steel having allowable axial stress is the 200 MPa————–? | 2.5 |
How many types of the stress are there in thin walled cylindrical shape pressure vessel—————-? | Two types; the axial and the hoop stress |
In the parabolic shape pressure vessel, the radius associated with the stresses are the—————- | Function of the equation generating parabola and point at which stress are to be calculated |
For the thin walled pressure vessel ration of the thickness to radius is the————— | Less than the 0.1 |
Why the square shafts are not in the practice————–? | Plane segments are not plane after the twisting |
During torsional loading in the shafts, at what point the shear stress is the maximum——————- | At surface of the shaft |
Which assumption is to prove torsional formula—————-? | Tan of angle is equal to the angle in the radians as the angles are so small |
Hollow shaft transfers more power than the solid shaft only if the————- | The weight and the material of both shafts will be the same |
Size of the steel shaft having the 2metre length designed to transmit 4000 Nm torque will depend upon the———- | Angle of the twist and Maximum allowable shearing stress |
Size of the hollow and the solid shaft of the same weight and length will be the—————— | Hollow will be greater in size as compared to the solid shaft |
Why the uniformly distributed load is replaced with the point load while solving the numerical problems——- | To make calculation simple |
While developing the free body diagram, the fixed end is replaced with the———— | Vertical and the horizontal reaction with the couple |
For the simply supported beam AB, if a point load P is acting acentric near to the B support then———————- | The reaction at B will be the higher |
If the uniformly distributed load is acting on a simply supported beam AB then the—————- | Both the reactions will be equal |
If the end moment of the loaded beam having two supports only is zero, then it is due to the————— | It is due to the support type |
If the uniformly distributed load of 50 N/ft is acting on 2 m length, its equivalent point load will be the————- | 328 N |
If the point load P is acting on simply supported beam AB then the———– | The shear force diagram will cross the zero-shear force line at the point where load is the acting |
If the point load P is acting on simply supported beam AB then the——— | The bending moment will be the maximum at the point where load is acting |
If the point loads acting at the mid span is replaced with the uniformly distributed load throughout the span on the simply support beam AB then the————— | Sudden decrease in shear force diagram at mid span will be changed from gradually decreasing trend forming the sloping line which will cross zero shear line at mid-span |
If the point loads acting at the mid span is replaced with uniformly distributed load throughout the span on the simply support beam AB then the——————– | The diagram will change the shape from linear to the curvilinear |
For the simply supported beam AB it is observed that the———– | Shear force diagram will cross the zero shear force line at the one point which will have maximum bending moment |
For the Neutral axis it is observed that the————– | There is the compression force above the axis and tensions forces below the axis |
The behavior of the forces either in compression & in tension from neutral axis is the—————– | Shows an increasing trend as moves away from the neutral axis |
The location of the neutral axis depends upon—————- | Shape of the beam |
Maximum flexural stress is located the———– | At the surface of the point in the beam with maximum bending moment |
For the designing of beam, that orientation of shape of the beam is selected for which the————- | The moment of inertia is maximum |
When parallel axis theorem is applied for the calculation of the moment of inertia—————– | In case of the T beams |
The changing the cross section (shape) of the loaded beam will the———- | The change the flexural stress |
For the circular beams Ixx and Iyy is the—————— | Same |
The bending of the long columns is known as the—————- | Buckling |
For designing of the columns, that orientation of the shape of the beam is selected for which the—————– | Moment of the inertia is minimum |
In the Euler’s formula L is the———— | Equivalent length of the column which depends upon end types |
The short, intermediate and long columns are differentiated on the————- | Slenderness ratio |
The structural member which is called the compression member is the—————— | Column |
The failure in short columns is called————- | Solid has the higher values |
The moment of the inertia of solid and hollow cross section is the———– | Solid has the higher values |
The section modulus is the———— | Shape factor |
The x component of the force making an angle 𝜃 with Y axis is equal to the————— | F sin 𝜃 |
At what angles under Centric Loading Normal and Shear Stresses are equal in the magnitude——————— | 45, 90 and 135 |
In case of the arbitrary loading, stresses are converted into force by multiplying with the————– | With the component of the area at which the stress is acting |
While finding the stresses on the given plan by using the formula approach, sign of the shear stress————– | Depends upon its upward & downward direction as well as on the direction of the normal stress acting on the same plan |
On the orthogonal planes—————– | Shear stresses have the same magnitude |
The max in plane shear stress and the max shear stress———- | In some cases, they are the same and in some cases they are the not |
How many stresses are shown to draw the max shear stress when it is not equal to the max in the plane shear stress————–? | 11 |
Which statement is the true———————? | Strain has no unit |
The minimum number of strain gages required for the plane strain analysis are the———— | 3 |
When the field is called level it means the————- | All the points will have same staff reading if there is the no change point |
The horizontal equivalent in the contour map—————- | Is the variable quantity depending upon the contour line |
In case of the even number of areas. Prismoidal formula————- | Is applied to even sections and left over volume is calculated by the trapezoidal formula |
When prismoidal correction is used for the volumetric calculation————— | When the volume was calculated by trapezoidal formula |
Which type of the odolite is now absolute—————–? | Non transit type |
The axis in which the telescope of the theodolite can be rotated in the horizontal plane———— | Vertical |
The foundation level depends upon the——————— | Required slope |
We need to fill if the——————- | Ground level is smaller than the foundation level |
If the ground has uniform slope then which the formula is used to calculate the cross sectional area—————– | Two level section |
Contour lines is the——————— | Must close within & outside of the map |
The type of the error when line of the sight is not parallel is known as the————— | Collimation error |
The height of the point above the datum is known as the————- | Reduced level |
The point which has the back sight as well as the fore sight data is known as the———— | Change point |
What is the loop misclosure if length of the loop is 5000 ft————————? | 14.8 millimeter |
Minimum furrow grade to assure the surface drainage is the————- | 0.05 percent |
Select incorrect statement——————-? | Lift irrigation increases water logging |
Drainage water intercepting the canal can be disposed of by passing canal below drainage in the———————–? | Super passage and canal syphon |